Exam 2 Solutions 11

Therefore when r2 infinity 0 changes of rin has no

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: R2 -- > infinity, 0 (changes of Rin has no effect on Vout) Therefore, we should have as LARGE R2 as possible. Problem 2(a) 0 1) KCL @Vb: 2) KCL @ Vc: 0 3) KCL @ Vout: 0 Vb 1k Vout Vb 1k 0 0 0 Three unknowns: Vb, Vd, and Vout; three equations. After solving for the system, we get Vout 50Vin ------------------------ Problem 2(b) 0 1) KCL @Vb: 2) KCL @ Vc: 0 0 Vb 1k Vout Vb 1k 0 0 0 3) KCL @ Vout: Three unknowns: Vb, Vd, and Vout; three equations. After solving for the system, we get Vout Vin ∙ Then, IL = Vout / RL = Vin ∙ -------------------------------------------------- Problem 3(a) We want to be able to change the gain without changing the internal design of the op-amp. In addition, negative feedback provides stable gain as well. Problem 3(b) Amp*100 = 15V. Amp, max = 0.15V. The maximum amplitude without clipping is 0.15V. Problem 3(c) When clipping occurs, a pure sinusoidal wave is no longer sinusoidal. The distorted wave now contains waves of some high frequencies (since such clipped waves can be modeled as a combination of numerous sinusoids of multiple frequencies. Because of these additional frequencies, the sound is no longer the same. Problem 3(d) dB = 20 log (Gain) = 20 log (100) = 40 dB. Problem 4 0) Label all the nodes as shown above. 1) From Golden Rule #1, Vc = Vb. 2) KCL @ Vb: 0 3) KCL @ Vc: 0 0 0 From the two KCL equations, We can solve for Vout. Vb = aVin Vout 2a 1 Vin Vout 2a 1 Vin ---------------------...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern