SolHW14ME2320

# SolHW14ME2320 - ∆ P v ≈ 78 kJ/kg ALTERNATIVE WAY...

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HOMEWORK 14 5 – 23 5 – 25 Given : V = 10 L; P 1 = 120 kPa; T 1 = 20 o C; P 2 = 1000 kPa; T 2 = 300 o C Find : PV . Solution : Assume air is ideal gas. Therefore enthalpy and internal energy depend only on T h = u + P v b P v = h – u or P v = h – u. From table A – 17: h 1 2 576.5 kJ/kg; u 1 2 413.5 kJ/kg

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Unformatted text preview: ∆ P v ≈ 78 kJ/kg ALTERNATIVE WAY . Solution : Assume air is ideal gas. Therefore enthalpy and internal energy depend only on T h = u + P v b P v = h – u or ∆ P v = ∆ h – ∆ u. ∆ P v = c p ∆ T – c v ∆ u=R ∆ T = (0.287)(300 – 20) ∆ P v = 80.36 kJ/kg...
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## This homework help was uploaded on 04/07/2008 for the course ME 232 taught by Professor Monefort during the Spring '08 term at Western Michigan.

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SolHW14ME2320 - ∆ P v ≈ 78 kJ/kg ALTERNATIVE WAY...

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