01 256mv 248v 45 02 256mv 248v slope after fb 05

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Unformatted text preview: tude Plot Inverting Freq (KHz) Vin (V) Vout (V) Gain vs Log Freq. 0.1 25.6mV 2.48V 45 0.2 25.6mV 2.48V Slope after f(b) 0.5 25.6mV 2.48V 40 =1 24.8mV 2.4V 17.8dB/decade 35 2 24.0mV 2.28V 30 5 24.0mV 1.88V 10 24.0mV 1.32V 25 20 24.0mV 760mV 20 Column V Column H 50 24.0mV 328mV 100 24.0mV 168mV 15 Break Frequency = 7 kHz (6.5 kHz from Specs) 10 Break Freq. (7KHz) 5 0 0.1 1 10 Log(Frequency) 100 Differentiating Amplifier Circuit (place screen shot here for break frequency illustration) Differentiating Amplifier Waveforms Func.Generator: 1 V pk-pk, Triangular Wave, 200Hz Func.Generator: 1 V pk-pk, Sine Wave, 200Hz zero offset zero offset Scope: DC coupling, Time Div 2.5ms Scope: DC coupling, Time Div 2.5ms Triangular Wave Input Volt age vs Diff. Amp Response 0.6 Volt a g e ( V) 0.4 0.2 (place waveforms here for triangular wave response) waveforms here for sine wave response) (place -0.02 -0.01 0 0 0.01 0.02 Column K Column E -0.2 -0.4 -0.6T ime(s) vout(t)= -CR(d(Vin)/dt), d(Vin)/dt described below Comments on Differentiating Amplifier: vout(t) = -CR(fcos(ft) The trend observed with increasing frequency and triangular wave peak to peak voltage is a positive linear relationship. Using the equation V(pk-pk)= 4*f*RC models this relationship with great accuracy. To derive this equation, the slope of the triangular wave is used to find a relationship between peak to peak voltage and frequemcy. ECE2100 Lab #4 - Operational Amplifier Circuits Page 4 of 4 Fall 2012 Comments on Differentiating Amp Output Voltage Amplitude - Triangular Wave Excitation Continued: The slope is equal to the V(pk-pk)*2*(1/t) using simple (Δy/Δx). By changing (1/t) (1/the period) to frequency Vin=(V(pk-pk)*2*f). Using kirchoffs current 0.25 laws on the Differnentiating Op Amp analysis Vout=-CR(d(Vin)/dt). Plugging Volt age pk-pk vs. freq. in our d(Vin)/dt from above the resulting equation is V(pk-pk)=4*f*RC after taking the absolute value because peak to peak is always positive. Doing this 0.2 multiplies the equatio...
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