Sample Exam 2 Fall 2006

# Sample Exam 2 Fall 2006 - Namet Ed\q+,on r1/r4/06 Problem#1...

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Namet Ed\q+,on r1/r4/06 Problem #1 (25 points) For the beam shown above: a) Determine an upper bound collapse load, pu, using the kinematic (mechanism) msthod. Your answer should be in terms ofthe beam plastic moment, Mo, and the beam lenglh, L. b) Draw the moment diagram conesponding to the chosen mechanism and the ca.lculated load. c) ls the collapse load that you have calculated the true collapsc load? provide justification for oul answer, d) If this beam is a compact l-shaped steel section in weak-axis bending, why is lateral bracing not required to aphieve MD? Aesq!^r q cllqpe< wrechqni:nr: fli'h. hrt t? + Erf eo,.I. mrl< I Wc. PA' 'l- 3PA =P(r:r'rr)= --'iP(n? = T,^ttrnq\ r.wrL r A.A Ll4 jLl+ lJsi2 +r, ^=p+ A= P'; T .., a= r3A s1."\l q*0! q?pY"l,l*tt'." I ." ''.0 (+a" a. ' x) l€ pa t- f,-^ ^ t/L= (-!r)t-o) + }1p(stp') - r1(ze+e')' lr(ze* ]e) = 5t1p8 CEE460 Steel Struchres I Exa:r'#2

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Name: So\q+ioh I l/14/0b A I ttc'-t \.nLy, a clii4rt\t k\tqtk t,\fc.[.qttA. . *qd hqw ]x{ h qrlrrs.d: d 'l' -in \,\/C: PA+3PA' wi -Grr?)t-a,) + |n-,r " rVtu Ag M"". ' A='ca 9'= )0 -_ p1a + 3 ir) Ft(P + a') -- /\:3-Lo - 4" , 2pA -- ze ]f,9 , |n-e Ye (P'zo') Vrlro t r (re)) ?lrr e zln^--o I 14 trr L 'rP- 3-r--T rrr(r- - R"= tt? I Fb 'a fll "' tlp 5L r'tt ir'-rqu ,LJ'- sr --- .i -') | r, \[ ]1r ,^h. r(,t 3-t "i.T' + Cqlc,rlrJ E v'o"r,i- Q C i \L s.

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## This note was uploaded on 04/07/2008 for the course CEE 460 taught by Professor Fahnestock during the Spring '08 term at University of Illinois at Urbana–Champaign.

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Sample Exam 2 Fall 2006 - Namet Ed\q+,on r1/r4/06 Problem#1...

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