This can be simply obtained by dividing 2 by v22 p1 2

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Unformatted text preview: ( 3) ρv 2 A2 ρv 2 Fy € 2 The above expression can be made comparable to the Fx expression if we get an expression for p2/ρv22. This can be simply obtained by dividing (2) by ρv22 /p1 : 2 €2 p p2 p1 1 v1 0.7 4 p1 1 1 1 = + − 1 = + (0.7 2 ) − 1 = 0.7 4 1 2 + 1 − 4 2 ρv 2 2 ρv 2 2 2 v 2 ρv12 ρv1 2 0.7 ( ) ‐1.6 This gives the final expression for Fy in terms of the inlet variables: Fy € 2 1 ρv A1 = p F A2 v 2 2 1 1 ( ) = 2y = 1 + 0.7 4 1 2 − 1.6 ( 4 ) 2 2 ρv A2 A1 v1 ρv 2 A2 0.7 0.7 ρv1 Fy 2 2 (d) Now that the Fx and Fy components due to the walls have been found the angle with which they act is: € θ = tan −1 € 0.49 p1 1.265 + ρv 2 π ρv1 A1 π 1 − − ≅ tan−1 Fx 2 −(1 + p1 ) 2 ρv12 A1 ρv12 Fy 2 No numerical values were given, thus the exact angle cannot be determined. However, the range that the angle must be as follows (measured counterclockwise from +y-axis to be positive) as Fx is <0): π 2 € <θ <0...
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This note was uploaded on 01/24/2014 for the course ME 106 taught by Professor Morris during the Spring '08 term at University of California, Berkeley.

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