Solutions a q w v air lv 002 kg m3 10 km3 2 10

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Unformatted text preview: T does this correspond to if 1kiloton of TNT releases 4x10 12J. Solutions: (a) Q= ρ w V air LV =0.02 kg / m3 × 10 km3 × 2 × 10 3 kJ / kg = 4 × 1011 kJ (b) mTNT = 4 × 1011 kJ =100 kiloton 4 × 1012 J / kiloton � �����������������������������������...
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This note was uploaded on 01/24/2014 for the course PHYSICS 7B taught by Professor Packard during the Spring '08 term at University of California, Berkeley.

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