D wall t water 0 t room dxka dt dq dt dq ka const

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Unformatted text preview: stant. d wall T water 0 T room ( ) ∫ dx=−kA ∫ dT dQ dT dQ =−kA =Const → dt dx dt Therefore, T −T room dQ =−kA water = 72 kW dt d wall (b) Your heater is a heat pump operating at its ideal Carnot performance. How much power must be supplied to the heater? Solution: The assumed ideal Carnot performance indicates that ́ Q T T room ́ d Q room 1− water η = room = , i.e. , W = ́ W T room −T water dt T room ( ) ́ Where Q room stands for the heat released per unit time to the room, which...
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This note was uploaded on 01/24/2014 for the course PHYSICS 7B taught by Professor Packard during the Spring '08 term at University of California, Berkeley.

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