Case Study 2 - Solutions

12 2666 391111 472 024 2790 782222 494 060 3163

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Unformatted text preview: t (hours) ∆p ‐ 100 ft (psi) ∆p ‐ 500 ft (psi) tD Pd ‐ 100ft Pd ‐ 500ft 0.12 266.6 3911.11 4.72 0.24 279.0 7822.22 4.94 0.60 316.3 19555.56 5.60 1.20 379.0 39111.11 6.71 2.40 503.8 78222.22 8.92 6.00 878.8 369.9 195555.56 15.56 6.55 12.00 1504.0 394.8 391111.11 26.63 6.99 24.00 445.1 782222.22 7.88 60.00 594.7 1955555.56 10.53 120.00 844.9 3911111.11 14.96 240.00 1344.8 7822222.22 23.81 The following equation applies for an infinitely acting reservoir in dimensionless variables: Filling in our values and assuming skin = 0: This will be used as the infinitely acting reservoir model. The following equation applies for semi‐steady state flow: Filling in our values and assuming skin = 0, FVF = 1, = 30.9 and = 1.781: Note: For case 1: For case 2: 3 Therefore the equations become: Case 1: Case 2: Using these models the following Semi log plot is created: Case Study 2 ‐ Part 2 30.00 25.00 pD 20.00 15.00 10.00 5.00 0.00 1000 10000 100000 1000000 10000000 t...
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