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# The component of the acceleration in the horizontal

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Unformatted text preview: r to its normal rolling position. The component of the acceleration in the horizontal direction of motion is given by ahoriz (t ) = ! B0 + B1 t from touchdown at t = 0 until the plane comes to rest at t = ts where B0 > 0, B1 > 0 . What was the horizontal speed of the airplane at time t = 0 when it first touched down 1) vhoriz (t = 0) = ! B0 2) vhoriz (t = 0) = ! B0ts + B1 3) vhoriz (t = 0) = B0ts ! B1 ts ts 2 2 2 2 4) vhoriz (t = 0) = ( ! B0 + B1 ts )ts 5) vhoriz (t = 0) = !( ! B0 + B1 ts )ts Answer 3. The change in the horizontal component of the velocity of the plane is found by integrating the horizontal component of the acceleration t " = ts vhoriz (t s ) ! vhoriz (0) = # t "=0 t " = ts ax (t " )dt " = # t "=0 (! B0 + B1 t " )dt " = ! B0t s + B1 2 ts . 2 The plane came to a stop at t = ts so vhoriz (t s ) = 0 . Therefore ! vhoriz (0) = ! B0t s + and so vhoriz (0) = B0t s ! B1 2 ts . 2 B1 2 ts 2...
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## This note was uploaded on 01/23/2014 for the course MATH 8.01SC taught by Professor Peterdournashkin during the Fall '10 term at MIT.

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