Unformatted text preview: r to its normal rolling position. The
component of the acceleration in the horizontal direction of motion is given by
ahoriz (t ) = ! B0 + B1 t from touchdown at t = 0 until the plane comes to rest at t = ts where B0 > 0, B1 > 0 .
What was the horizontal speed of the airplane at time t = 0 when it first touched down
1) vhoriz (t = 0) = ! B0
2) vhoriz (t = 0) = ! B0ts + B1 3) vhoriz (t = 0) = B0ts ! B1 ts ts 2
2 2 2
4) vhoriz (t = 0) = ( ! B0 + B1 ts )ts
5) vhoriz (t = 0) = !( ! B0 + B1 ts )ts
Answer 3. The change in the horizontal component of the velocity of the plane is found
by integrating the horizontal component of the acceleration
t " = ts vhoriz (t s ) ! vhoriz (0) = # t "=0 t " = ts ax (t " )dt " = # t "=0 (! B0 + B1 t " )dt " = ! B0t s + B1 2
ts .
2 The plane came to a stop at t = ts so vhoriz (t s ) = 0 . Therefore ! vhoriz (0) = ! B0t s +
and so vhoriz (0) = B0t s ! B1 2
ts .
2 B1 2
ts
2...
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This note was uploaded on 01/23/2014 for the course MATH 8.01SC taught by Professor Peterdournashkin during the Fall '10 term at MIT.
 Fall '10
 PeterDournashkin

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