quiz5 solutions

The component of the acceleration in the horizontal

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: r to its normal rolling position. The component of the acceleration in the horizontal direction of motion is given by ahoriz (t ) = ! B0 + B1 t from touchdown at t = 0 until the plane comes to rest at t = ts where B0 > 0, B1 > 0 . What was the horizontal speed of the airplane at time t = 0 when it first touched down 1) vhoriz (t = 0) = ! B0 2) vhoriz (t = 0) = ! B0ts + B1 3) vhoriz (t = 0) = B0ts ! B1 ts ts 2 2 2 2 4) vhoriz (t = 0) = ( ! B0 + B1 ts )ts 5) vhoriz (t = 0) = !( ! B0 + B1 ts )ts Answer 3. The change in the horizontal component of the velocity of the plane is found by integrating the horizontal component of the acceleration t " = ts vhoriz (t s ) ! vhoriz (0) = # t "=0 t " = ts ax (t " )dt " = # t "=0 (! B0 + B1 t " )dt " = ! B0t s + B1 2 ts . 2 The plane came to a stop at t = ts so vhoriz (t s ) = 0 . Therefore ! vhoriz (0) = ! B0t s + and so vhoriz (0) = B0t s ! B1 2 ts . 2 B1 2 ts 2...
View Full Document

This note was uploaded on 01/23/2014 for the course MATH 8.01SC taught by Professor Peterdournashkin during the Fall '10 term at MIT.

Ask a homework question - tutors are online