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Unformatted text preview: " r 2t where the
thickness of shell is approximately t ! 10 km = 104 m and the radius of shell equals the
radius of the earth, Re ! 6 " 103 km = 6 " 106 m . So the volume is approximately ( Ve ! 4" r 2t = 4" 6 # 106 m ) (10 m ) = 4 # 10
2 4 18 m3 . Question 3 What is your best estimate for the number of molecules in the earth’s
atmosphere?
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9. Less than 101 molecules.
Between 1010 and 10 20 molecules.
Between 10 20 and 10 30 molecules.
Between 10 30 and 10 40 molecules.
Between 10 40 and 10 50 molecules.
Between 10 50 and 10 60 molecules.
Between 10 60 and 10 70 molecules.
Between 10 70 and 10 80 molecules.
More than 10 80 molecules. Answer 5. One mole of an ideal gas STP (Standard Temperature and Pressure) occupies
22.4 L ! 20 " 10#3 m 3 , so the number of moles of air in the atmosphere is approximately
4 ! 1018 m 3 / 20 ! 10"3 m 3 # 2 ! 1020 moles . There are approximately 6 ! 1023 molecules/mole . Therefore there are approximately
( 2 ! 1020 moles)(6 ! 1023 molecules/mole) " 1044 molecules...
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This note was uploaded on 01/23/2014 for the course MATH 8.01SC taught by Professor Peterdournashkin during the Fall '10 term at MIT.
 Fall '10
 PeterDournashkin

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