chap19_entropy&Gibbs

00 103 no 2 o 2 0100 2 0100 ln400 10 829 3 g

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Unformatted text preview: S° = 205.2J/(mol•K) SO2(g) + ½ O2(g) ⇒ SO3(g) • SO3; ∆ H°f = ­395.7 kJ/mol, ∆ S° = 256.8 J/(mol•K) • • Is it spontaneous under standard conditions? 32 ∆H°rxn = [(1mol × -395.7 kJ )] − [(1mol × -296.8 kJ )] = −98.9kJ mol ∆S °rxn =[(1mole × 256.8 J )]-[(1mol × 248.2 J )+(1/2mole × 205.2 J )]=-94.0 J mol • K mol • K mol • K K ∆G°rxn = − 98.9 ×103 J − (298 K × -94.0 J ) = −70888 J K The rxn is spontaneous at 25 o C. mol 33 Calculating ∆ G°rxn from free energies of formation • Free E of formation of pure elements in standard sta...
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This note was uploaded on 01/17/2014 for the course PHY 53890 taught by Professor Appling during the Fall '13 term at University of Texas.

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