{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Quiz_11.10 - CE331,Fall2010 Quiz11.10 A [email protected] 24ft...

Info iconThis preview shows pages 1–6. Sign up to view the full content.

View Full Document Right Arrow Icon
CE 331, Fall 2010 Quiz 11.10 1 / 1 Analysis of Steel Braced Frame Bldg Calculate the maximum moment due to factored loads, M u , in a typical: 1) floor joist 2) floor girder 3 @ 14 ft 24 ft 3 @ 14 ft 24 ft Plan View Side Elevation Front Elevation 3 @ 26 ft A B 1 2 3 4 F y = 50 ksi all members F u = 65 ksi DL = 4” thick lt. wt. slab LL = 35 psf WL = 30 psf Shape Purlins W18x35 Girders W12x87 Columns W16x36 X Bracing L2x2x1/8 A g = 0.484 in 2
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
1. The unbraced length of the joist compression flange L for lateral torsional buckling is: flange, L b , for lateral torsional buckling is: 1 L b = L 1. L p 2. L b = L r 3. L b = 0 4. L b = joist spacing
Background image of page 2
2. The equation used to calculate the flexure h f i l j i φ M i strength of a typical joist, M n is: 1. φ M = φ M M n p 2. φ M n = φ M p – BF (L b – L p ) 3. φ M n = φ F cr A g 4. φ M n = 0.90 A g F y
Background image of page 3

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
3. The unbraced length of the girder compression flange L for lateral torsional buckling is: flange, L b , for lateral torsional buckling is: 1 L b = L 1. L p 2. L b = L r 3. L b = 0 4. L b = joist spacing
Background image of page 4
4. The equation used to calculate the flexure
Background image of page 5

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 6
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}