Unformatted text preview: erage of 1 misprint every 400 characters. Page ten of the booklet contains 2000 characters. Let X denote the number of misprints on page ten. You may assume that the distribution of the misprints is a Poisson distribution. (a). P( X = 4 ) = (Answer should be exact and in terms of e.) Solution: We have λ = 5 , and so P ( X = 4) = e −5 54 24 (b). P( X ≥ 3  X ≤ 6 ) = (Approximate using tables.) Solution: P ( 3 ≤ X ≤ 6 ) P ( X ≤ 6 ) − P ( X ≤ 2 ) 0.762 − 0.125 P( X ≥ 3  X ≤ 6) =
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P ( X ≤ 6)
P ( X ≤ 6)
0.762 Name ________________________
March 7, 2013
5. (a). A box contains two red cards and 4 blue cards. Cards are randomly drawn one at a time with replacement until a red car...
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This note was uploaded on 01/25/2014 for the course MATH 511 taught by Professor Sumner during the Spring '13 term at South Carolina.
 Spring '13
 Sumner
 Math, Probability

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