Math511Exam2Solutions

K 1 so e x 6 5 4 3 2 1 21 b suppose

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Unformatted text preview: λ = , and so we get 2 8 e−2 4 λ = 2, and so P ( X = 3) = = 2 6 3e 6. An archer hits the target on 60% of his shots. Let X equal the number of times the archer hits the target in 20 shots. 2 (a). Determine the mean and variance of X. µ = 12 σ = 4.8 (Reduce to decimals) Solution: µ = np = 20 × 0.6 = 12, σ 2 = npq = 12 × 0.4 = 4.8 (b). P( X = 9) = (exact value – don’t simplify) Solution: ⎛ 20⎞ 9 11 P ( X = 9 ) = ⎜ ⎟ ( 0.6 ) ( 0.4) ⎝ 9⎠ Name ________________________ March 7, 2013 7. (a). A box contain...
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