Assignment-1-solutions

450 09 6 0 6 3 0183 0917 1169 242285 12 9 0189 0764

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Unformatted text preview: 8 15 0.195 0.629 1039 914947 24 21 0.201 0.510 967 1079090 30 27 0.207 0.408 890 1135899 36 33 0.213 0.323 805 1093561 42 39 0.219 0.255 710 962339 48 45 0.225 0.204 600 754575 54 51 0.231 0.171 465 484683 60 57 0.237 0.154 268 169156 STOOIP (m3) if used ∆h = 0.1 7473892 7438127 Part B Since no information is given concerning a gas cap or free gas in the reservoir, all gas produced must come from solution. Therefore the STGIIP is: 12 ENGI 9114 – Advanced Reservoir Engineering Assignment # 1 Solutions – Winter 2011 Part C First take the production profile and determine how much oil was produced per year: Year Oil Produced (Sm3) Cum Oil (Sm3) 1 912500 912500 2 912500 1825000 3 626888 2451888 4 359525 2811413 5 211700 3023113 6 120450 3143563 Then determine the net present value: 13 ENGI 9114 – Advanced Reservoir Engineering Assignment # 1 Solutions – Winter 2011 Performed in Excel: Part D Determine the recovery factor by calculating the ratio of cumulative oil produced to STOIIP: 14...
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