Assignment-1-solutions

For an ideal gas simplifying to 9 engi 9114 advanced

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Unformatted text preview: 4 – Advanced Reservoir Engineering Assignment # 1 Solutions – Winter 2011 Part F The formula for a real gas is: In order for a the ideal gas formula to be used for the real gas formula, the Z factor must be close to 1 or must be close to 0. Therefore the following range is suggested: 10 ENGI 9114 – Advanced Reservoir Engineering Assignment # 1 Solutions – Winter 2011 Question 3 What we know: Circular cross section of bowl shaped reservoir. Plot of reservoir is provided: 70 60 Height (m) 50 40 30 20 10 0 -1200 -1000 -800 -600 -400 -200 0 200 400 600 800 distance (m) The base line represents the oil water contact Porosity of rock increase upwards, represented by The water saturation as a function of h is Net to gross Formation volume factor is Solution gas oil ration is Part A The formula for STOIIP is: Taking out the constant and breaking the reservoir up into 11 slices of constant thickness : 1000 1200 ENGI 9114 – Advanced Reservoir Engineering Assignment # 1 Solutions – Winter 2011 This is most easily solved in excel. Choose a thickness of slices to evaluate, say 6 m. Then evaluate the properties in the centre of the slice . Note that is obtained by reading from the plot provided. For the total STOOIP, simply sum up the STOIIP calculated at each layer. An example is provided below: FVF NTG ∆h h Slice Thickness Height hi (m) Φ(hi) Sw(h) xi STOOIP/layer 1.450 0.9 6 0 6 3 0.183 0.917 1169 242285 12 9 0.189 0.764 1106 637357 1...
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