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Unformatted text preview: f this distance (4.6 mm). Equation 19.3a is used to solve for Tf, where the
value αl for the 1025 steel [12.0 × 106 (°C)1] is found in Table 19.1.
Equation 19.3a leads to = 32.2°C + 10°C = 42.2°C (108°F) Thus, solving for Tf from 3. After summer 2011 midterm exam: βSiC is a ceramic material used in hightemperature
applications. It has the socalled zinc blende structure (see adjacent diagram). This structure is
FCC with a twoatom basis having Si at (0,0,0) and C at (1/4,1/4,1/4).
A) Show that the βSiC unit cell c...
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 Fall '12
 MatthewR.Libera

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