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Unformatted text preview: 100 seconds and R = 20 litres/sec into the above formula gives V = 1928 litres. Ultimately the tank will contain kR = 27,260 litres. Reaching 99.33% of this value requires five times constants = 5 * 1363 seconds = 6815 seconds (1.89 hours). (c) The defining equation becomes V 0.0007335V ki (T V ) V (0.0007335 ki )V kiT V 0.1007335V 0.1T The system is still analogous to the charging capacitor example but the time constant and static gain are different. 1 / 0.1007335 9.9927 seconds k / 0.1 (litres/sec) / litre k 0.1 0.9927(no units) V(t) kT( 1-e t/τ ) The time required to reach 500 litres is found by setting V(t) equal to 500 litres and solving for t. The result is 6.955 seconds. Ultimately the tank will contain kT = 992.7 litres. Food for thought: The volume cannot stabilize at 1000 litres because, in the steady state, the input and output flows must be equal and this is not the case when V = 1000 litres. At 992.7 litres the input flow ((1000‐992.7) * 0.1 = 0.73 litres) and the output flow (0.00073 * 1000 = 0.73 litres) become equal and the volume remains the same thereafter. Question 3 Tg is the torque exerted by the shaft on the generator (equal and opposite to the torque exerted on the shaft by the generator). Question 4 Question 5...
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This note was uploaded on 01/24/2014 for the course SYSC 3600 taught by Professor John bryant during the Fall '08 term at Carleton CA.

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