{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

PracticeProblemsMidterm_solu

Note shown on the right note term on the right note

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: be right. Note shown on the right. Note term on the right. Note that B has the time constant and isis slower thanC that B has the time constantthat B has the time constant 1 and is slower than C 1 1 and slower than C 1/3 B with time constant 1/3. The curve for A + B would with time constant 1/3. Thewith time constant 1/3. The curve for A + B would curve for A + B would be a shifted version the B be a shifted version of the be a shifted version of of the B curve as shown. Finally, B curve as shown. Finally, curve as shown. Finally, 1 y t) is obtained taking (A A is ) + C wherewe ( ) B obtained by we y (t) (is obtained byby takingy (t++ B ) + Cwheretaking (A + B ) + C where we C −1 note that the C curve come close zero quickly and quickly note that the C curve come close toto zeroC curve and close to zero quickly and note that the come hence the y curve come close A + B quickly. quickly. hence the y curve come close toto A + B curve come close to A + B quickly. hence the y A 9. What is the steady state y when and the input u(t) are given...
View Full Document

{[ snackBarMessage ]}

Ask a homework question - tutors are online