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Unformatted text preview: be right. Note shown on the right. Note
term on the right. Note
that B has the time constant and isis slower thanC
that B has the time constantthat B has the time constant 1 and is slower than C
1 1 and slower than C
1/3 B
with time constant 1/3. The curve for A + B would
with time constant 1/3. Thewith time constant 1/3. The curve for A + B would
curve for A + B would
be a shifted version the B be a shifted version of the
be a shifted version of of the B curve as shown. Finally, B curve as shown. Finally,
curve as shown. Finally,
1
y t) is obtained taking (A A is ) + C wherewe
( ) B obtained by we
y (t) (is obtained byby takingy (t++ B ) + Cwheretaking (A + B ) + C where we
C
−1
note that the C curve come close zero quickly and
quickly
note that the C curve come close toto zeroC curve and close to zero quickly and
note that the
come
hence the y curve come close A + B quickly.
quickly.
hence the y curve come close toto A + B curve come close to A + B quickly.
hence the y A 9. What is the steady state
y
when
and the input u(t) are given...
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This note was uploaded on 01/27/2014 for the course MAE 171A taught by Professor Idan during the Winter '09 term at UCLA.
 Winter '09
 IDAN

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