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# 2 6 1 hour 3 3 b the fraction of time that the sta

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Unformatted text preview: = 136 = 22 . 2 6 = 1 hour, 3 3 (b) The fraction of time that the sta↵ is busy is ⇢ = µ = 1 .5 3 = 1. 2 (c) Use Kingman’s Formula, we have Wq ⇡ ⇢ µ c2 + c2 0. 5 1 + 1 /2 1 a s = = hour. 2 3 1. 5 2 4 Average waiting time of a customer W = Wq + E (S ) = (d) E[Driving time] 1 3 Lq = W q = 1 . 5 ⇥ = . 4 8 So average number of customers waiting is 3 . 8 1 4 + 1 3 1/6 = (1) 7 hour. 12 5/12 (2) 2. We want to decide whether to employ a human operator or buy a machine at a service counter. Customers arrive at a constant rate of one every 14 minutes. A human operator takes an average time of 700 seconds to serve a customer, with a standard deviation of...
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