Final solutions

# 5 10 28 2 927 10 24 158 10 6 a 3amath a

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Unformatted text preview: n the body- centered cubic structure with a lattice constant of 0.287 nm, and thus have a magnetic moment of two Bohr magnetons per atom. Calculate the Weiss constant. Determine the Curie constant and the saturation magnetization at 0 K. Iron is a body centered cubic lattice with a lattice constant of 0.287 nm. Hence, there are 2 atoms per unit cell, and the atomic density is 8.5 × 1028 atoms/m3. The Curie temperature in a ferromagnetic is related to the Weiss constant by Tc = 2 nµ m µ0 λ , kB so that The Curie constant is given as 6. λ= C= 1.38 × 10 −23 ⋅ 1043 = 392 . 8.5 × 10 28 (2 ⋅ 9.27 × 10 −24 )2 4π × 10 −7 2 nµ 0 µ m Tc 1043 = = = 0.887 3k B 3λ 3 ⋅ 392 and the saturation magnetization (at 0 K) is M (0 ) = nµ m = 8.5...
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