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Thus ns 100 ns 110 ns 111 ns 100

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Unformatted text preview: ere is now an additional atom in the center of the rectangular cell, so that Also, for the (111) plane, there is not an additional atom at the center of the triangle, as the body- centered atom lies either above or below the most common (111) planes. Thus ns ,(100 ) = ns ,(110 ) = ns ,(111) = ns ,(100 ) = ns ,(110 ) = 1 = 4.47 × 1014 / cm 2 2 (0.473nm ) 1 = 3.16 × 1014 / cm 2 2 2 (0.473nm ) 1 1 = 2.58 × 1014 / cm 2 2 (0.473nm )2 cos( π ) 6 1 = 4.47 × 1014 / cm 2 (0.473nm )2 2 = 6.32 × 1014 / cm 2 2 2 (0.473nm ) ns ,(111) = 1 1 = 2.58 × 1014 / cm 2 2 (0.473nm )2 cos( π ) 6 (c) For the face- centered cubic lattice, the (100) surface plane has an additional atom...
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