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# Then using table b4 we find that 2 10 ni2 15

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Unformatted text preview: 3. (a) Determine the position of the Fermi level with respect to the valence band energy level. (b) Determine p0. (c) Is this n- type or p- type material? (a) We first note that here the electron concentration is less than the intrinsic concentration, so that the material is p- type. Then, using Table B4, we find that 2 10 ni2 (1.5 × 10 ) p0 = = = 1.13 × 1015 cm −3. n0 2 × 10 5 Then, using the last equation on p.125, we find that "p % " 1.13 × 1015 % EF − Ev = −kBT ln \$ 0 ' = −kBT ln \$ = 0.237eV . 19 ' # 1.04 × 10 & # Nv & (b) From above, 2 10 ni2 (1.5 × 10 ) p0 = = = 1.13 × 1015 cm −3. 5 n0 2 × 10 (c) This is p- type material. 4.41 In a germanium sample at T = 250 K, it is found that p0 = 4n0 and that Nd = 0. Determine...
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