100mnh3aqaftertheadditionof0010mol nh4clsfornh3pkb474

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Unformatted text preview: entration of N2O4(g)? A) .9 × 10-2 M 1 B) .3 × 10-2 M 3 C) .6 × 10-2 M 2 D) .3 × 10-6 M 2 E) .7 × 10-2 M 1 28) 0.272 g of a monoprotic solid acid (mw = 189 g/mol) is dissolved in water to produce 25.0 mL of a solution with pH = 4.93. Determine the ionization constant of the acid. A) .1 × 10-8 4 B) .4 × 10-9 2 C) .8 × 10-7 2 D) .4 × 10-10 1 E) .1 × 10-4 2 29) What is the pH of a 0.253 M solution of ammonium chloride? Kb = 1.2 × 10-5 A) .7 2 B) 1.3 1 C) .1 9 D) .9 4 E) .9 9 - 10 30) In 0.100 M HC2H3O2(aq), [H3O+(aq)] = [C2H3O2-(aq)] = 1.3 x 10-3 M. If a few drops of concentrated HCl(aq) are added to this solution, the C2H3O2-(aq) concentration is C) .100 M. 0 D) 1.3 x 10-3 M. A) 1.3 x 10-3 M. B) 1.3 x 10-3 M. < > = 31) Calculate the pH of a 1.00 L solution of 0.100 M NH3(aq) after the addition of 0.010 mol NH4Cl(s). For NH3, pKb = 4.74. A) .26 9 B) .26 8 C) 0.26 1 D) 1.56 1 32) A solution has [HC7H5O2] = 0.100 M and [Ca(C7H5O2)2] = 0.200 M. Ka = 6.3 × 10-5 for HC7H5O2. The solution volume is 5.00 L. What is the pH of the solution after 10.00 ml of 5.00 M NaOH is added? 33) For the reaction PCl5(g) → PCl3(g) + Cl2(g) at 298 K, Keq = 1.87 × 10-7, ΔS° = 1.8192 J/mol K, what is ΔG° and is the reaction spontaneous? - 11 34) Predict whether ΔS is positive or negative for the following process: H2(g) + 1/2 O2(g) → H2O(g) A) here is not enough information to determine t B) S changes the same on both sides of the equation Δ C) ositive p D) egative n E) S doesnʹt change Δ 35) Consider the following reaction: 4 NH3(g) + 7 O2(g) → 4 NO2(g) + 6 H2O (l) -16.7 0.0 ΔG° for this reaction in kJ is: 51.8 -237/.2 kJ/mol 1. (gr Pb/ Mw Pb) x 2 x Mw(PbSO4) = 121 g 2. moles of I2 = 2 x 8/5 = 3.2 3. The molarity of the solution in the container after the addition of the solution of KCl is 5mL x M / 1000 = Moles KCl = 2.54exp(-5)/39 M = 1.30exp(-4) Total amount of K present in the container is : 1mL x 2M / 1000 = 1.30exp(-4) x V / 1000 V = 15.4 L 4. moles of Cu available = 42.6/63.5 = 0...
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This document was uploaded on 01/29/2014.

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