6 2h2 o2 2h2o h 571 co c o2 h 1105 co2 h 3935 c

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Unformatted text preview: .67 Moles of HNO3 available 84/63 = 1.333 Stoichiometry ratio must be 3/8 HNO3 is the limiting reagent gr Cu(NO3)2 = 187.5 x moles gr = 93.8 moles = moles HNO3 /8 x 3 = 1.333/8 x 3 5. 6. - 4OH + Br 2 + M n 2+ ----- MnO2 + 2Br - 12 + 2H2O total coeff = 11 moles H2SO4 = moles NaOH / 2 2 V x 0.110 = 10 x 0.085 7. - V = 3.9 mL moles HNO3 = 23.4 x 0.601 / 1000 = 0.0140 Moles Cu = moles HNO3 x 3/8 = 0.00527 gr Cu = 0.00527 x 63.5 = 0.334 8. 81.4% moles gas = PV / RT = 0.5 Mw = gr /moles = 64.2 SO2 is the only possibility 9. Mole He = 1.37 x 2.05/760 / 0.082 / 297.5 = = 0.0151 Moles Ne = 721/1000 x 0.185 / 0.082 / 309.2 = 0.00526 Total mole = moleHe + mole Ne = PV/RT from which P = 0.253 atm 10. Using PV = nRT calculate the V at the initial conditions = 8.11 L Work = V DP x 101.3 (conversion factor for joules) = -2.73 103 11. CO2 + 2H2O -CH3OH + 3/2 O2 ΔH° = +726.6 2H2 + O2 -2H2O ΔH° = -571 CO -C + ½ O2 ΔH° = +110.5 ---CO2 ΔH° = -393.5 C + O2 __________________________________________________________________ 2H2 + CO 12. C8H18 ----- +...
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