5 pts 136 p42 suppose the flow of current milliamps

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: have a value of 0.9990, any of the values are correct (1.5 pts.) 1.36 (p.42). suppose the flow of current (milliamps) in wire strips of a certain type under specified conditions can be modeled with a normal distribution having μ = 20 and = 1. a) What proportion of strips will have a current flow of between 18.5 and 22 milliamps? proportion (18.5 < x < 22) = proportion (-1.5 < z < 2) = proportion (z < 2) – proportion (z < -1.5) = 0.9772 – 0.0668 = 0.9104 6 b) What proportion of strips will have a current flow exceeding 15 milliamps? The table only goes down to -3.89, the proportion to the left of -3.89 = 0.0000. Since prop (z < -5) < prop (z < -3.89), prop (z < -5) = 0.0000. prop (z > -5) = 1 – prop (z < -5) = 1 – 0 = 1. c) How large must a current flow be to be among the largest 5% of all flows? proportion (z < c) = 0.95 ==> c = 1.645 (or 1.64 or 1.65) (2 pts.) 1.38 (p.42). An article suggest that x = Al (Aluminum) matrix grain size (...
View Full Document

This note was uploaded on 01/29/2014 for the course STAT 350 taught by Professor Staff during the Fall '08 term at Purdue University-West Lafayette.

Ask a homework question - tutors are online