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Wheeler_HW_3 - £3 Ah = 45.3 In Hg S = 13.6 From Eq 9.2 for...

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Unformatted text preview: £3 Ah = 45.3 In Hg S = 13.6 From Eq. 9.2 for p, <<pm AP = Mme = Abs/2.9 = (453m Hg)1 36(62431bm I #592171? I sec” ) (32.17le ——fl‘ ”bf-sec” X1441!!! lfl’)(12inlfl) =223 psid 21.3. From Eq. 9.3:AP = Rsiang For this linear device. the sensitivity is constant: R 1 1 AP 'slnepg"sinso°xo.ax1moxss1"oozssmma 0.5 mm in the reading R wrresponds to O.D5cmf.0255 crana = 1.967Pa _,2 First convert the pressure value from cm water to Fe: P=Rpg = 0.1x1000 x93: 980Pa' Using Eq. 9.35 AP = Rsinapg ' 960 =Rsin30x 0.9 x1000x 9.8 R: 250mm 3:11 Considering Eq. 9.3 systematic error due to error in the angle of inclined manometer: AP— Rpg sins. where R is the indicated length on the inclined tube. For the actual and indicated cases we have: AP” =Rpg sin ‘15.5 and AP“ =Rpg sin '15. Systemafioenorasapementageofmaoiny : M- = w— = 0. 03250r3 . . . AP,“ sin ‘15. 5 An alternative to'the above solution: «SAP: Rpg 5 sin 9- =- Rpgcos 06 I? for small changes in 0 JAP —=oot AP 95 0 aAP_mt.15,o.5x AP 180 =3 0.0926 or 3.26 96 of reading ...
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