Ch_6_part2

Haghighi 1 ni 1 1 4 1 n j 1 1 4 1 nk

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Unformatted text preview: = −1 2b η = −1 −a ≤r ≤ a Chapter 6 Page 3 K. Haghighi 1 Ni = (1 − ξ )(1 − η) 4 1 N j = (1 + ξ )(1 − η) 4 1 Nk = (1 + ξ )(1 + η) 4 1 Nm = (1 − ξ )(1 + η) 4 Chapter 6 Page 4 K. Haghighi Triangular Element: Define 3 length ratios, L1 , L 2 & L 3 such that: s L1 = h 0 ≤ L1 ≤ 1 S = perpendicular distance from one side h = altitude of that side L1 , L 2 & L 3 = Area coordinates Chapter 6 Page 5 K. Haghighi A1 (base ) (height ) = bs ⎫ = ⎪ 2⎪ ⎬ bh ⎪ A = area of triangle = ⎪ 2⎭ 2 bs A1 2 = s =L = 1 A bh h 2 Chapter 6 Page 6 K. Haghighi A3 A2 A1 , L2 = , L3 = L1 = A A A A1 + A 2 + A 3 = A L1 A + L 2 A + L 3 A = A L1 + L 2 + L 3 = 1 A1...
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This document was uploaded on 01/29/2014.

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