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me320hw2keyUpdated

# me320hw2keyUpdated - HW#2 Key ME 320 1 Schematic Given 5 kg...

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HW #2 Key ME 320 1. Schematic: Given : 5 kg of steam inside the cylinder Process occurs in which: Q= 80 kJ and W shaft =-18.5 kJ The internal energy of the system changes from u 1 =2709.9 kJ/kg to u 2 =2659.6 kJ/kg Assume: Neglect kinetic and potential energy For a closed system, the 1st law is: Specifically for this problem, the 1st law is: This can be rearranged for W piston : Substituting values gives: The system pushes the piston outwards to perform 350 kJ of work on the surroundings. 2. Find: Ideal Gas Law for 90% elastic collisions Nomenclature : P=pressure, F=force, A=area, p=momentum, t=time, v=velocity, v x = x-component of velocity vector, L=length, N=number of particles, V=volume, m=mass, T=temperature, k=Boltzmann constant, R=universal gas constant

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We will proceed similarly to how the derivation was done in class. Start with the equation for pressure: so P= The time between collisions can be expressed as: Therefore the frequency of collisions with one wall for N particles will be ½*v x /L. From this, we can get: Next, we want to express the momentum change in terms of velocity and mass. However, first we must
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