Solution a the plane is a two dimensional subspace of

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ctor in the plane from part (a), and a vector normal to that plane. Solution: (a) The plane is a two dimensional subspace of R3 . The vectors (1, 0, 1) and 10 (0, 1, 2) are independent and in the plane so they form a basis. Set A = 0 1 so the 12 projection matrix is −1 ￿ ￿ 10 ￿ ￿ 10 5 −2 1 1 101 101 0 1 2 2 . = −2 P = A(AT A)−1 AT = 0 1 012 012 6 12 12 1 25 −2 −5/6 −2 −5/6 −7/6 (b) P −2 = −2/6 so −2 = 2/6 + −14/6 is the sum we want. 1 1/6 1 1/6 7/6 3) For the questions below, just write the complete word ‘TRUE’ or ‘FALSE’ or leave it blank. No explanations are needed for this question only. A correct answer is worth...
View Full Document

Ask a homework question - tutors are online