Sol-161ME2-F02

Sol-161ME2-F02 - % MA 161M EXAM 2 Oct. 22, 2002' Name...

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Unformatted text preview: % MA 161M EXAM 2 Oct. 22, 2002' Name Differentiate the following: sing: + cos a: (8 pts) 1) y = $2 Wsflwrflwn~awywwfl fig (7 pts) 2) y : {75 tang: (7 pts) 3) y : (111.7[:)(ta,n‘1 :17) <mm>®y=wmm .._ WWW W" A 7 x / 254' r“ ywv- 7‘9“ 9‘ '2“: )0ij ¢E r~- ’ w ?{/:(X_l)agy’ {Z4ZJWX "” .3 ANSWER 75 -4, I“ a” gin! 44mm WMW w 71"” 1%? ~+ W7 ANSWER y]: l Mtg/{+sz— X ("PX flu l:’// 7134m~'7/'7‘ "/7, ANSWERM___ {I ewpyg’q if”; 1:) ANSWER _L_________— '5 MA 161M 7 EXAM 2 ' Oct. 22, 2002 (7 pts) 5) y : 005(271‘m2 + 45%; (2/1va Rial/1H7?! '7 ’3 k v 2 5.2—(4/777570 W (“7% f z) ANSWER 6) Differentiate and simplify your answer: (10 pts) (a) y : 111x/a:2 + 22: (j : l ,4“ [Klflyd } . H I J- / (lY‘fL) . Z > 2 (ny2y ) v ,3 [x'+/) % ' XKW‘Z) , _ 6H”. ANSWER 3L ‘ ’4’” L) (8pm) (b) y=mm L j}, g :(44‘¥).(fl“y) ’filn L g”: 2&4} )1 i X we y /" (Z’Z—fl)x / 2,4»! X X 7’ z 2(7 ,flz’tx “'I a? /:(2 is”) X ANSWER . . tan36 (5 pts) 7) Flnd 31—15(1) 0 e 3 cW39 «v 1.; @1419“: 69:31? £14136 5 09379 (9 " /I‘/J4 M3,? = / 9‘70 3" A {6/03 9):, _ ANSWER '3 *- MA 161M EXAM 2 - Oct. 22, 2002 (10 pts) 8) Find the slope of the tangent to the curve defined by a: +siny : 33y at the point (0, 0) on the curve. H (WWW 9”” y/(u>13,—vl): ’( a" = 1/" awg/X flltJHJ) -' %0 2 'T(— :‘I ANSWER ' (10 pts) 9 The half life of Polonium 210 is 140 days. How many days will it take for a sample to decay to 5% of its original value. Since you are not allowed to use a calculator, give your answer in the form indicated. Decaj 97H 1‘! Wz‘): Xaé’kffl) ‘fiflwk, WW? Wt?” ' We): h We 95/” {Hf/W4" I 7"=em‘ MM 2,: «%R:~%z {2) MM W4: W Vii): ,uyxa We M, (/1 M5 gmfln:nefif '5 MA 161M EXAM 2 Oct. 22, 2002 (10 pts) 10) A 13 ft. ladder is leaning against a house when its base starts to slide away. When the base is 12 ft. from the house, the base is moving at the rate of 5 ft. / sec. How fast is the top of the ladder sliding down the wall then? 1} Alex-#7,: r, l”) {3 [YR/)1? (y/wj'i/u; (U ,x Xh} 4Xg723%:0 (2) 77M a;va % vay/évjrlzj W :{fl/: (81—: v-ya‘g #thrlz flew/«Mm wept: (1/4 + g/aj’ztw at g, (3) u yvffizr 7./.f/;r M M(SJ ffl/‘Z’ :19— «Li/4’ J/V/m WZW/H /Z (10 pts) 11) Find the linearization of f : \3/5 at 3: = 27. Use your linearization to approximate {’56. Leave “your answer in the form of an improper fraction. L {y}: ,(‘/a)+f//5‘)[y~fi) ‘24? P I _ £/n)=f/2’?:s ##ng / arm-3'5? gaff—l7 \: ~ l /><'-27> L//) 337’ .‘ - ’?_-'/ : W0 1/10): {*5/25 27)’ 27 27 ll ANSWER "5’7 ...
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Sol-161ME2-F02 - % MA 161M EXAM 2 Oct. 22, 2002' Name...

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