75 in b 0375 in y a m y a x 0375 in 0375 in v 0375

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Unformatted text preview: 17.5 kN 27.5 kN V (kN) 27.5 -2.5 27.5 -17.5 -2.5 -17.5 V (kN) 3 6 x (m) 2.75 3 2.75 6 x (m) 1.5 m 3m 150 mm 12- 24) Hibbeler 4th ed NA Centroid of cross- secRon: 150 mm 30 mm 30 mm Moment of InerRa of cross- secRon about NA: flange web 1. 1.5 m 3m 150 mm 12- 24) Hibbeler 4th ed NA 150 mm 30 mm 30 mm Q/t is maximum at NA: Can use area below NA! 1. 13- 40,41) Hibbeler, 4th ed The 500- kg engine is suspended from the jib crane at the posiRon shown. Determine the state of stress at points A and B on the cross secRon of the boom at secRon a–a. Point B is just above the bofom flange. E 150 mm 20 mm 2m 2m 2m a 30 C a 150 mm D 0.4 m A 300 mm 20 mm B 20 mm Section a–a Given: mass of engine, dimensions of frame and cross- secRon. Find: Stress components at A and B. Expect axial and flexural normal stresses and transverse shear stress. Plan: Find support reacRons first, then take a secRon at a- a and find internal reacRons. Then find stress components. 13- 40,41) Hibbeler, 4th ed FBD of Beam 30° 2m Cx FDE .4 m 4m Cy 500g 2m Cx Cy M 2m 500g N V z 0.75 in. B y y Cx 4m Cy 500g 13- 40,41) Hibbeler, 4th ed FBD to leg of a-a 2m Cx Cy 2m 500g M N V z 0.75 in. B 0.375 in. y A M y A x 0.375 in. 0.375 in. V 0.375 in. B B x 13- 40,41) Hibbeler, 4th ed SecRon ProperRes 150 mm 20 mm 150 mm A 300 mm 20 mm B 20 mm Section a–a 13- 40,41) Hibbeler, 4th ed Normal Stress 13- 40,41) Hibbeler, 4th ed Shear Stress 13- 36,37) The drill is jammed in the wall and is subjected to the torque and force shown. Determine the state of stress at points A and B on the cross secRon of drill bit at secRon a–a. y Hibbeler, 4th ed 400 mm a 20 N · m x a 125 mm y A z 5 mm 3 5 4 B Given: Torque applied to bit, and Section a–a force applied to handle, and dimensions. Find: Stress components at A and B. Expect axial and flexural normal stress, and torsional and transverse shear stress. Plan: Take a secRon through points A and B and find internal reacRon at the centroid of that cross- secRon. Calculate stress components at each point. 150 N y 13- 36,37) Hibbeler, 4th ed 400 mm a 20 N · m FBD: x a 125 mm 0.4 m 20 N·m y z x y 0.125 m 3 150 N A z 4 150 N y Section a–a A V M B y 5 4 B z y A 3 5 mm 0.5 in. 0.75 in. 20 N·m th 13- 36,37) Hibbeler, 4y ed z x SecRon ProperRes: y A z 0.125 m 3 y 150 N 400 mm 4 a 20 N · m x a A y A 5 mm z B y A 125 mm y x z B B Section a–a B 3 5 mm 5 mm 5 mm y A 5 mm x B y y A A 5 mm z B x B 5 mm 5 mm 5 4 150 N m 20 N·m y 150 N 13- 36,37) Hibbeler, 4thz ed z 3 4 x m 0.125 m y 0.125 m 3 A 15...
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This note was uploaded on 01/30/2014 for the course EMCH 210 taught by Professor Osama during the Winter '08 term at Penn State.

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