Lab 6 capacitors

# 11 mm 0 885 x 10 12

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Unformatted text preview: r the three different parts of our experiment: - - - - - - - - - - - - - - - - - - - - - - - - - - - - - A = area of metal being used in capacitor = 39750 mm d = distance between metal plates = .11 mm ε0 = 8.85 x 10^- 12 - - - - - - - - - - - - - - - - - - - - - - - - - - - - - Calculating k for the 3 experiments: C1d ( 33.3 × 10 −9 )(.11) k1 = = = 10.4 ε 0 A (8.85 × 10 −12 )( 39750) k2 = C2 d (14 × 10 −9 )(.22) = = 8.7 ε 0 A (8.85 × 10 −12 )( 39750) k3 = C3 d (17 × 10 −9 )(.11) = = 10.6 ε 0 A (8.85 × 10 −12 )(19875) - - - - - - - - - - - - - - - - - - - - - - - - - - - - - € Finding the average for constant k: kaverage = 10.4 + 8.7 + 10.6 = 9.9 3 - - - - - - - - - - - - - - - - - - - - - - - - - - - - - € Dielectric constant Error Propagation of uncertainties: ⎛ྎ d ⎞ྏ 2 ⎛ྎ c ⎞...
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## This document was uploaded on 01/31/2014.

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