FALL_2013_PHY1321_assignment5_solutions

Fy may n 392 n 0 n 392 n f k k n 0300

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Unformatted text preview: ° = 0 (d) Wg = mgΔr cos θ = ( 392) ( 5.00) cos ( −90°) = 0 (e) ΔK = K f − Ki = ∑ Wother − ΔEint 1 mv2 − 0 = 650 J − 588 J + 0 + 0 = 62.0 J f 2 5 If it takes 4.00 J of work to stretch a Hooke'+s- law spring 10.0 cm from its unstressed length, determine the extra work required to stretch it an additional 10.0 cm. U=½kx2 4= ½k(0.1)2 and so U = ½ (800) (0.2)2 U= 16J ΔU = 16J-4J = 12J 4=½k0.01 so that k=800N/m...
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This note was uploaded on 01/31/2014 for the course PHY 1321 taught by Professor Czajkowski during the Fall '08 term at University of Ottawa.

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