ARCH3355_2013_04_16_Foundation_Design

# C d d d compression in top of footing d distance d

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Unformatted text preview: sure ld 12” #4 bars [7in o.c.] d d d compression in top of footing d distance “d” from the d As = 20,250(12) / [.90(60,000)(10.5 – 1/2)] 14” face of the wall [critical b a section for shear] As = 0.45in2 per linear foot of d/2 footing 3” cover face of wall [critical #5 bars [8in o.c.] s table) There are many possible combinations of bar sizes and spacings (refer ltoection for moment] e f à༎ #5 bars at 8in on center d This achieves the steel garea of 0.46in2 / linear footcover footing à༎ WORKS! 3” of two-way or punching h d #5 bars [8in o.c.] b ARCH3355 upward soil pressure | c Constructiontension III | Spring 2013 ld d FOUNDATION face of column: [critical section for moment] reinforcing effective depth “d” is the distance from top of the footing to the centroid of DESIGN | P. RAAB the reinforcing steel e 12” 12” d 3” cover ld ld Find the required depth, width, and reinforcement for the following load: Concrete strength: Steel Strength: Dead Load: Live Load: Max Soil Pressure: f’c = 3000psi, fy = 60,000psi, 12” 14,000 lb/ft of wall length, 7,000 lb/ft of wall length, 2 3,500 [7in/ft #4 bars lb o.c.] d face of column: [critical section for moment] ld 3” cover Designing Wall Footings: Example Concrete strength: Steel Strength: Dead Load: Live Load: Max Soil Pressure: f’c = 3000psi, fy = 60,000psi, 14,000 lb/ft of wall length, 7,000 lb/ft of wall length, 3,500 lb/ft2 12” 36” 5’ below grade #8 bar [1in dia] d d d d d 3” cover ld Find the required depth, width, and reinforcement for the following load: ld 12” 12” #4 bars [7in o.c.] d d 14” #5 bars [8in o.c.] development length o reinforcing steel 12” d d 14” Step 06: Find the Development Length for Tensile Reinforcement: #5 bars [8in o.c.] d ld 12” ld Id = 0.04Ab [fy/√fc] Area of #5 Bar: Area [Ab] = 0.31in; Diameter [db] = 0.625in Id = 0.04(0.31)[60,000/√3000] = 13.58in NOTE: Cannot be less than: 0.0004dbfy or 12in 0.0004(0.625)(60,000) = 15in à༎ USE 15in [the governing value] d d 14” Step 07...
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## This note was uploaded on 02/04/2014 for the course ARCH 3355 taught by Professor Staff during the Spring '08 term at Texas Tech.

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