Since j 1 k 1 q toggles its value from 1 to 0 problem

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Unformatted text preview: ive clock edge arrives at 40 ns. Since J = 1, K = 1, Q toggles its value from 1 to 0) Problem No. 7 The truth table for the NAND gate circuit described in this problem is as follows: A 0 0 1 1 B 0 1 0 1 Q 1 1 0 0/1 (No change) Qn 1 0 1 1/0 (No change) This circuit behaves like a latch. It retains its state, when A = B = 1. In comparison, the NOR latch of Figure A.23(b) retains its state when both of its inputs are logic “0”....
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This document was uploaded on 02/01/2014.

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