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Unformatted text preview: cies: p= 0.25 + ½(0.50) = 0.50 q= 0.25 + ½(0.50) = 0.50 8) After random mating, and using the genotypic frequencies you calculated from the above answer, 200 progeny are produced. How many individuals of each genotype are now in the new population, given the expected frequencies above (round up one for fractional numbers) (2 points)? Genotype Number of flies A1 A1 50 A1 A2 100 A2 A2 50 9) A pathogen sweeps through the population above (containing a total of 200 flies) and SOME flies are resistant to the pathogen. Only red and pink
eyed flies live. So, all of the A1 A1 and A1 A2 individuals survive and none of the A2 A2 survive. What are the new allele frequencies after this strong selection? Did evolution occur? (2 points). Genotype A1 A1 A1 A2 A2 A2 Frequency Allele Frequencies (p, q are frequencies of A1 and A2) 0.33 p= 0.33 + ½(0.67) = 0.67 q= 0 + ½(0.67) = 0.33 0.67 0 Yes, evolution occurred, allele frequencies changed from p = 0.5 and q =0.5 to 0.67 and 0.33 respectively. 10) Calcul...
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 Spring '10
 Reinthal
 Ecology, Evolution, Work

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