Suppose six hundred voters are chosen at random and

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Unformatted text preview:   3. In a large metropolitan area 70\% of the registered voters are thought to favor a new zoning ordinance. Suppose six hundred voters are chosen at random and interviewed. What is the probability that fewer than half support the ordinance? p = .70 n = 600 Ļƒ 2 = np (1 āˆ’ p ) = 600(.70)(.30) = 126 Ļƒ = 126 ā‰ˆ 11.22 X = number of supporting voters 300 āˆ’ 420 āŽž āŽ› P( X < 300) = PāŽœ Z < āŽŸ ā‰ˆ P( Z < āˆ’10.70) ā‰ˆ 0 11.22 āŽ  āŽ 4. A group of 50,000 tax forms has an average income of Āµ=$37,0...
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This document was uploaded on 02/03/2014.

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