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Unformatted text preview: 3. In a large metropolitan area 70\% of the registered voters are thought to favor a new
zoning ordinance. Suppose six hundred voters are chosen at random and interviewed.
What is the probability that fewer than half support the ordinance?
p = .70
n = 600 Ļ 2 = np (1 ā p ) = 600(.70)(.30) = 126
Ļ = 126 ā 11.22
X = number of supporting voters
300 ā 420 ā
P( X < 300) = Pā Z <
ā ā P( Z < ā10.70) ā 0
ā 4. A group of 50,000 tax forms has an average income of Āµ=$37,0...
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This document was uploaded on 02/03/2014.
- Winter '14