Lecture 6

# A x1 2 dx1 b x2 2 dx2 x12 b x1 2

This preview shows page 1. Sign up to view the full content.

This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: > + < x2 > !2 < x1 x2 > =< x 2 > a + < x 2 >b !2 < x > a < x >b so if parIcle 1 is at x= ­1 and parIcle 2 is at x=2 then the square of the distance b/w them is 3^2 (as expected!) Case 2: IdenIcal parIcles 1 [! a ( x1 )! b ( x2 ) + ! b ( x1 )! a ( x2 )] 2 1 ! " ( x1 , x2 ) = [! a ( x1 )! b ( x2 ) " ! b ( x1 )! a ( x2 )] 2 ! + ( x1 , x2 ) = Bosons Fermions 2 < ( x1 ! x2 )2 >=< x12 > + < x2 > !2 < x1 x2 > 1# 2 x1 | ! a ( x1 ) |2 dx1 " | ! b ( x2 ) |2 dx2 + " x12 | ! b ( x1 ) |2 dx1 " | ! a ( x2 ) |2 dx2 2 \$" ± " x12! a ( x1 )*! b ( x1 ) dx1 " ! b ( x2 )*! a ( x2 ) dx2 ± " x12! b ( x1 )*! a ( x1 ) dx1 " ! a ( x2 )*! b ( x2 ) dx2 < x12 >= Boaom two terms are =0 b/c states are or...
View Full Document

## This document was uploaded on 02/04/2014.

Ask a homework question - tutors are online