Lecture15

Kt 1 as weve seen at low t the number of parucles in

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Unformatted text preview: .306! 1/2 ) This is as big as the integral gets! If we lower the temperature further, we cannot keep the density constant. We lose parUcles! SOLUTION: The ground state populaUon is separate from the excited states. 7 Two ­fluid model ! N = # fn = N g (T ) + N e (T ) = N g (T ) + " D( E ) f ( E , T ) dE n 0 excited state populaUon ground state populaUon DistribuUon funcUon in the ground state (E=0): fg (0, T ) = 1 e! µ /kT ! 1 As we’ve seen, at low T the number of parUcles in the ground state is large. ! µ / kT V " 2 mkT % Ne = 2 $ 2 ' 4! # ! & 3/2 ) x dx *0 ex e(µ/kT ( 1 3/2 e "1 e! µ /kT " 1 V " 2 mkT % Ne = 2 $ 2 ' 4! # ! & V " 2 mkT % 1.306V " 2 mkT % N e = 2 $ 2 ' ( 1.306! 1/2 = $ ' 4! # ! & 4 # !!2 & 3/2 ) x dx *0 ex ( 1 3/2 8 Two fluid model At TE we have all the atoms in the normal state N e = N 2...
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