Unformatted text preview: 0. q = Pr(B scores) = 1/2 Pr(A wins) = Pr(A wins  A scores, B scores) x Pr(A scores, B scores)+ Pr(A wins  A scores, B doesn't score) x Pr(A scores, B doesn't score) + Pr(A wins  B scores, A doesn't score) x Pr(B scores, A doesn't score) + Pr(A wins  Neither A or B score ) x Pr(Neither A or B score). = 1/2 x pq + 1 x p(1
q) + 0 x (1
p)q + 1/2 x (1
p)(1
q) = 139/240. c) Since there is a possibility of draw, let E = A wins F = B wins. Answer = Pr(E occurs before F) Pr(A wins) = Pr(A wins  A scores, B scores) x Pr(A scores, B scores)+ Pr(A wins  A scores, B doesn't score) x Pr(A scores, B doesn't score) + Pr(A wins  B scores, A doesn't score) x Pr(B scores, A doesn't score) +...
View
Full
Document
This note was uploaded on 02/03/2014 for the course EECS 140 taught by Professor Staff during the Spring '08 term at UC Irvine.
 Spring '08
 staff

Click to edit the document details