Part b a 50 mm b 500349852 4994 mm 5009 49916

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Unformatted text preview: PART B µA = 50 mm; µB = (50.03+49.85)/2 = 49.94 mm; σΑ = (50.09-49.91)/6 = 0.03 mm; σΒ = (50.03-49.85)/6 = 0.03 mm; µASSEMBLY (CLEARANCE) = (50−49.94) = 0.06 mm; σASSEMBLY (CLEARANCE) = (0.032 + 0.032)1/2 = 0.04242 mm. z = (x- µASSEMBLY (CLEARANCE))/ σASSEMBLY (CLEARANCE) For interference, x 0 mm. That is, we look for z (– 0.06)/0.04242 = -1.414 P(z - 1.414) from the standard distribution tables is ~ 0.0787. Thus ~7.9% of the assemblies will likely experience interference. 2. Three identical parts, A, B, and C, are assembled end-to-end to give a length of 3.900±0.015 in. Using the worst-case analysis (which allows for 100% assembly of parts), what should be the...
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