EE153exam1sum2006 - Name Keg Sum 2.00 EE 153 mum b Exam#1...

Info icon This preview shows pages 1–5. Sign up to view the full content.

View Full Document Right Arrow Icon
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
Image of page 3

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 4
Image of page 5
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Name: Keg ! Sum 2.00 EE 153 mum b Exam #1 100 pts Show all work, Provide unis to all answers and make legible. 1. Find the Thévenin and Norton Equivalent Circuits. -j2 ohms 50 ohms K'LL'. "QM-105+ V” iv Y T O l001ab”1a‘o 1 \lab ragjié : O ,4.- J (Cin~ \a-E’J)Iqb 1'0. 9%Val: Find 16C: 115C: Egg: IDLE: : 401.3% ,.__ Lb sat-2gb 3" 0'035 gab; [Qt-2,: CW “9“?) — 50+5‘iéjn _.--'—’_-_-——_-_-“ mp , ~' O'Q‘b“ 159613353 MsMD 012514 (3) [email protected] 2. Write a set of mesh current equations for the circuit and place them in matrix form. 1° 142002 T. : 15 T1: —- 41x .L, T 0 8433+ fL’IEH‘ (IJ’I4)R5 + (1—3—19)de J a. ~.L« r waui‘Q‘ + (85+?4 Lqungerfilbe “W514: 0 (14—1239” (14-15395 «v3 + 149wL23:O -: V5 ‘ ”2212 W P513 + (Ez+Qa+Ju)La)—£4 3. For the following circuit and inputs determine v0(t) using Superposition. Vs1 (t) v51(t)=10cos(103t) V v52(t)=5008(104t V is(t)=200cos(10t)mA (330 + “0,330“ (3‘ ) : (29.53 H j G) Frecfiu‘nca Lo: 1543 — ’ (51‘) 5') 5 ngv - u , d _ 29. 3509 -9559 5 Jr W ' 353—33 V0,: Kw 5&9: =2)wa ———--"" too-31.04 4 o) \/ Lam = 5.0m» (10:: fl 0le 755.3 rl-S" v V01 : V01; ‘\’ V017— %ZC+)= 3.3 505 (1032+ _. 1-3”) V V021; 0.3123. (1.91531?) '— 0.33 [:33 V \WSC+):5605(/04»—0.é°) + 3.3 weCHPtv-IE") V __.__ _‘__.___,_,___..,_.. 4. Write a set of node voltage equations and solve for the phasor values of the outputs. For co=1007t, write V3 as V3(t). ~j1DU ohms 34200»? SUohms nch® gag/1+ fl+3vx+ Vito ,Vx=\1."/1 20 1‘60 5 Gosh/0.05% + 303W? jo‘ot V3 + aV'—a\/2, + 0. 9311—10 '1.95 v. + (—WS mooovl *~ (—3043wa = O NW© ‘Q‘JK + V3~V2 + V3 + V3 : O vQWOO Q20 90 =0 . _'o.os‘( + moi—‘13 9V1~3V. + 30.0\\)3 ’JO.O\ V2. J 3 - = O '3Vn + (330.0% + (0.02 —o.o4*JW5 smwm v,: 20° (—1.75+J~o.otwl jam v3 = ~385L,’ (23' 0'0! W2 + (0.02jo.04\\(5= (012.9, 200 rlI7S+JOoD\ ~L’JO-Ol R/Z]_[—E‘8i:D/fi] 3 ”Q 0.0! 001—3004 \/5 (o L../ \ 5. a) Find the transfer fimction defined by the output voltage over the input voltage, Ham). 1 lij b) The driving-point impedance of a network is Z0co)=50+j10 Q. What are the resistance, reactance, conductance, and susceptance of this Y('u>)~ _‘~ network? resigkmce __ 500— J i Z50) Veadance = \00- = 0.0; iii) Cohduchn u = o. 02 S : 0.01 «5 0004 S 3,50,7an = - 0.004 5 Is the network inductive, resistive, or capacitive? Why? ‘lfldutfivé 3 ‘Wm Qvgwi At this frequency, what two components (and their values) could be used to model the network? Does this simple model work for other frequencies? Why or why not? \0 ‘UQL:‘\O 50$ hon J J W :L)‘ L9 c) Write the time domain ODE if the transfer function shown is an Impedance Value: H (s) = 2—S+2—. = 1/. s + 3s +10 I Qw+ll>I : (LJwVJr ngmrio) \/ ...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern