algebra 5

# algebra 5 - Chapter One Linear Systems 76(c This is a...

• Notes
• 2

This preview shows pages 1–2. Sign up to view the full content.

76 Chapter One. Linear Systems (c) This is a reasonably complicated network. 9 volt 3 ohm 3 ohm 2 ohm 2 ohm 3 ohm 4 ohm 2 ohm 2 In the first network that we analyzed, with the three resistors in series, we just added to get that they acted together like a single resistor of 10 ohms. We can do a similar thing for parallel circuits. In the second circuit analyzed, 20 volt 12 ohm 8 ohm the electric current through the battery is 25/6 amperes. Thus, the parallel portion is equivalent to a single resistor of 20/ ( 25/6 ) = 4.8 ohms. (a) What is the equivalent resistance if we change the 12 ohm resistor to 5 ohms? (b) What is the equivalent resistance if the two are each 8 ohms? (c) Find the formula for the equivalent resistance if the two resistors in parallel are r 1 ohms and r 2 ohms. 3 A Wheatstone bridge is used to measure resistance. r 1 r 3 r g r 2 r 4 Show that in this circuit if the current flowing through r g is zero then r 4 = r 2 r 3 /r 1 .

This preview has intentionally blurred sections. Sign up to view the full version.

This is the end of the preview. Sign up to access the rest of the document.
• Fall '12
• Durant
• Algebra, Resistor, ohm, Electrical resistance, Series and parallel circuits, Willow Jay Shelburne

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern