singularity functions

# 3 843750 1685885 6530209 29 106 464 6 y10

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Unformatted text preview: lection at any point along the beam can be calculated using Eq. 23f (elastic curve equation). Therefore, the deflection 0 y at x = 10 ft is (10) 4 2000 10 − 15 + − 2000 24 24 4 23,437.5 10 − 4 3 + 168,588.5(10) − 653,020.9 y (10) = 1 EI y (10) = (12)2 [− 833,333.3 + 843,750 + 1,685,885 − 653,020.9] 29 × 106 (464 ) + 6 y10′′ = 0.011165 ft = 0.1339 in 18 Slide No. 36 LECTURE 16. BEAMS: DEFORMATION BY SINGULARITY FUNCTIONS (9.5 – 9.6) Singularity Functions ENES 220 ©Assakkaf Example 5 A beam is loaded and supported as shown in Figure 17. Use singularity functions to determine, in terms of M, L, E, and I, a) The deflection at the middle of the span. b) The maximum deflection of the beam. Slide No. 37 LECTURE 16. BEAMS: DEFORMATION BY SINGULARITY FUNCTIONS (9.5 – 9.6) Singularity Functions ENES 220 ©Assakkaf Example 5 (cont’d) y M E, I A x C B L L Figure 17 19 Slide No. 38 LECTURE 16. BEAMS: DEFORMATION BY SINGULARITY FUNCTIONS (9.5 – 9.6) Singularity Functions ENES 220 ©Assakkaf Example 5 (cont’d) First find the reactions RA and RB: y M x A E, I L RA + C B L RB ∑M C = 0; RA (2 L ) + M = 0 M 2L + ↑ ∑ Fy = 0; RA + RB = 0 ∴ RA = − ∴ RB = M 2L Slide No. 39 LECTURE 16. BEAMS: DEF...
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## This document was uploaded on 02/04/2014.

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