This preview shows page 1. Sign up to view the full content.
Unformatted text preview: …2 x=
2/1 ==> =2 X=
= x= 0.0025
1 = 0.0025
= 0.9975
= 99.8% Solution #8: = 95% = 0.05
Q/3
Q/3 = 0.3Q Q/3 = 0.2Q p = 1 =
= 0.05 = = ........................(1) ( = = = 0.1357 = = = 0.0358 = = = 0.0068 = 0.5Q * 0.1357= 0.06785Q
= 0.3Q * 0.0358= 0.01074Q
= 0.2Q * 0.0068= 0.00136Q
Q = 0.07995Q = 0.08
= 1= 92% = 1 0.08 = 0.92 ) Solution #9: For crossflow scrubbers:
,
If everything else is constant, Therefore, Hence anticipated collection efficiency at the new flowrate, Solution #10: For crossflow scrubbers, if everything else is constant, Therefore, Therefore required percent increase of the water flow to the scrubber is given by:
=...
View Full
Document
 Spring '13
 TahirHusain

Click to edit the document details