Assignment 2-solution

# 05 ppm temperature inversion height 700 m pressure 1

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Unformatted text preview: 5 ppm Temperature inversion height = 700 m Pressure = 1 atm Temperature = 300 K ( For region below 700 m) 1 DU = 2.69 ( Hence 0.05 ppm = 0.05 ⁄ ) molecules of ozone per molecule of air Number of molecules of ozone per unit earth's surface area = ( ⁄ =( = 2.44 ) ) molecules of ozone per of earth's surface earth's surface = ( ⁄ Volume of air for 1 ⁄ ⁄ ) ⁄ number of molecules of air = ( = 1.71 = 0.07 molecules of air per ) of earth's surface ⁄ Concentration of ozone up-to a height of 700 m = ( ) = 3.50 DU ⁄ Fraction of ozone molecules below inversion height = ( ) = 1.426 Hence below the inversion height we have 1.426 molecules of ozone per million air molecules. Ther...
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## This note was uploaded on 02/06/2014 for the course ENG 9624 taught by Professor Tahirhusain during the Spring '13 term at Memorial University.

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