Unformatted text preview: area of earth = 8.07 =8.07 where r is Earth’s radius which 6370 5.1 4. Sketch the following molecules: CFC113, CFC114, HCFC22. and HCFC123. Solution #4:
1. CFC113 C = 1+1 = 2
H = 11 = 0
F=3
Cl = 63 = 3 2. CFC114 C = 1+1 = 2
H = 11 = 0
F=4
Cl = 64 = 2 3. HCFC22 C = 0+1 = 1
H = 21 = 1
F=2
Cl = 412 = 1 4. HCFC123 C = 1+1 =2
H = 21 = 1
F=3
Cl = 613 = 2 5. D uring 1990  1993 the production of CFC  11 dropped, averaging only 1.9
g/year over these four years. By the beginning of 1994, emissions were
sufficiently low to be neglected. Write the expression for C(t) over the entire range
19902050. For consistency with the notation in Example 11.9 in the class notes, let...
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 Spring '13
 TahirHusain
 Steady State, Ozone depletion, Chlorofluorocarbon, CFC

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