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2013+F+314+Ex+2+Pr_2Bsol

# r1 2 r2 6 r3 18 r4 3 r5 24 r6 27

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Unformatted text preview: rrent flows from terminal a to terminal b when they are connected with a wire. Thus the 6 Ω resistor is shorted out and carries no current. KVL, or mesh current equation: +(10 V ) + I ⋅ (4 Ω) = 0 thus I = −2.5 A € Note that the directions of the mesh current I and the Norton equivalent current are opposite, because the mesh current flows clockwise from terminal b to terminal a. Thus the Norton equivalent current equals +2.5 A. Answer: A © 2013 Alexander Ganago Page 6 of 30 Last printed 2013- 12- 08 6:33 PM File: 2013 F 314 Ex 2 Pr+sol+instr.docx 2013 Fall EECS 314 Exam 2 Problem 4 In the circuit shown on the diagram, Vs = 12 V Is = – 4 A (note the sign!) R1 = 2 Ω R2 = 6 Ω R3 = 18 Ω R4 = 3 Ω R5 = 24 Ω...
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