2013+F+314+Ex+2+Pr_2Bsol

2013 F 314 Ex 2 Pr_2Bsol

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: and Ohm’s law, VOUT = ( −100 mA ) ⋅ (100 Ω ) = −10 V Due to KVL and Ohm’s law, I1 = VOUT − V− − 10 V = = −10 mA RF 1 kΩ From KCL at the output node, (100 mA) + I 2 = I1 I 2 = (−10 mA) − (100 mA) = −110 mA Answer: A © 2013 Alexander Ganago Page 10 of 30 Last printed 2013- 12- 08 6:33 PM File: 2013 F 314 Ex 2 Pr+sol+instr.docx 2013 Fall EECS 314 Exam 2 Problem 6 In a series RLC circuit, a student observed unwanted oscillations. Further analysis showed that in this circuit ω 0 = 5 ⋅α Which of the following measures is sufficient to get rid of oscillations? A. Increase L by a factor of 20; keep R and C unchanged B. Increase R by a factor of 20; keep L and C unchanged C. Increase C by a factor of 20; keep R and L unchanged D. Increase L by a factor of 20 and increase...
View Full Document

This note was uploaded on 02/06/2014 for the course EECS 314 taught by Professor Ganago during the Spring '07 term at University of Michigan.

Ask a homework question - tutors are online